A: You don’t bury survivors.
But if you were the only survivor, how long could you survive by eating the other passengers?
We’re going to assume it’s winter and the bodies stay frozen so they don’t decay. A Boeing 747 can carry 416 passengers, meaning there are 415 potential menu choices. Assuming our cannibal doesn’t eat the bone, he’ll be getting all of his calories from the rest of the tissue. A normal-sized person is about 68 kg (~150 lbs). Skeletons weigh about 14% of the total body weight, leaving about 59 kg of edible other stuff. Since protein is 4.0 Calories per gram and fat is 9.0 Calories per gram, we’ll assume that the average caloric density is 6.0 Calories per gram. From this we can compute the total Calories in each person,
Cal. per person = (edible mass of person) · (Cal. per g)
= (59 kg) · (6.0 Cal per g)
= 3.5×105 Cal. per person.
Multiplying by 415 people, we can compute the total number of Calories,
total Cal. = (Cal. per person) (# of people)
= (3.5×105 Cal. per person) · (415 people)
= 1.5×108 Cal.
Assuming a 2000 Calorie per day diet, we can compute just how long it would take to eat and successfully digest all the other passengers,
time = (total # of Cal.) / (# Cal. per day)
= (1.5×108 Cal.) / (2000 Cal. per day)
= 200 years.
It would take 200 years to eat all the passengers. So, if you’re the only survivor in a plane crash, look on the bright side. At least you wouldn’t starve to death.